C# program to check whether the number is Armstrong no or not

In this article check whether the input number is Armstrong no or not by using console application in c#.net using while loop:

Step1: Take a new console application using c# as a language in the Visual studio.

Step2: Declare the variables int_Number, int_Temp, int_Remainder, int_Sum and initialize the “int_sum” value to 0.

Step3: Read an input from the User in this Variable “int_Number” for storing that number which you want to test for Armstrong number, now assign that value to “int_Temp”.

Step4: now run the while loop till the value of “int_Temp” doesn’t become 0 and then digit by digit take the values and multiply that digit value three times and then add it to the “int_sum” variable and in the next step  divide the “int_Temp” variable by 10. In the end check if the “int_sum” value is equal to the “int_Number” then it means that it is Armstrong number.

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

namespace Armstrong_Number

{

    class Program

    {

        static void Main(string[] args)

        {

            int int_Number, int_Temp, int_Remainder, int_Sum;

            int_Sum = 0;

            Console.WriteLine("please the numbers to be tested for Armstrong number");

            int_Number = int.Parse(Console.ReadLine());

            int_Temp = int_Number;

            while (int_Temp != 0)

            {

                int_Remainder = int_Temp % 10;

                int_Sum = int_Sum + int_Remainder * int_Remainder * int_Remainder;

                int_Temp = int_Temp / 10;

            }

            if (int_Number == int_Sum)

            {

                Console.WriteLine("Entered number is an armstrong number. ");

            }

            else

            {

                Console.WriteLine("Entered number is not an armstrong number. ");

            }

            Console.ReadLine();

        }

    }

}

Output: